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8v^2+16v-384=0
a = 8; b = 16; c = -384;
Δ = b2-4ac
Δ = 162-4·8·(-384)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-112}{2*8}=\frac{-128}{16} =-8 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+112}{2*8}=\frac{96}{16} =6 $
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